//
// main.cpp
// 299 - Train Swapping
//
// Created by Panks on 05/06/12.
// Copyright (c) 2012 __MyCompanyName__. All rights reserved.
//
#include <iostream>
#include <vector>
#include <cstdlib>
using namespace std;
int mergeSort(int arr[], int array_size);
int _mergeSort(int arr[], int temp[], int left, int right);
int merge(int arr[], int temp[], int left, int mid, int right);
int main (int argc, const char * argv[])
{
int t,l,tmp,inv ;
vector<int> store;
cin>>t;
while (t--) {
inv=0;
cin>>l;
while (l--) {
cin>>tmp;
store.push_back(tmp);
}
inv=mergeSort(&store[0], (int)store.size());
cout<<"Optimal train swapping takes "<<inv<<" swaps.\n";
store.clear();
}
return 0;
}
int mergeSort(int arr[], int array_size)
{
int *temp = (int *)malloc(sizeof(int)*array_size);
return _mergeSort(arr, temp, 0, array_size - 1);
}
int _mergeSort(int arr[], int temp[], int left, int right)
{
int mid, inv_count = 0;
if (right > left)
{
mid = (right + left)/2;
inv_count = _mergeSort(arr, temp, left, mid);
inv_count += _mergeSort(arr, temp, mid+1, right);
inv_count += merge(arr, temp, left, mid+1, right);
}
return inv_count;
}
int merge(int arr[], int temp[], int left, int mid, int right)
{
int i, j, k;
int inv_count = 0;
i = left;
j = mid;
k = left;
while ((i <= mid - 1) && (j <= right))
{
if (arr[i] <= arr[j])
{
temp[k++] = arr[i++];
}
else
{
temp[k++] = arr[j++];
inv_count = inv_count + (mid - i);
}
}
while (i <= mid - 1)
temp[k++] = arr[i++];
while (j <= right)
temp[k++] = arr[j++];
for (i=left; i <= right; i++)
arr[i] = temp[i];
return inv_count;
}
Wednesday, June 6, 2012
299 - Train Swapping
Just count the no. of inversion in array, using mergesort.
Labels:
solution,
Sorting-related Problems,
source,
UVa
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